-3(2x^2+1)=11x

Solution for -3(2x^2+1)=11x equation:

-3(2x^2+1)=11x

We move all terms to the left:

-3(2x^2+1)-(11x)=0

We add all the numbers together, and all the variables

-11x-3(2x^2+1)=0

We multiply parentheses

-6x^2-11x-3=0

a = -6; b = -11; c = -3;
Δ = b2-4ac
Δ = -112-4·(-6)·(-3)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-7}{2*-6}=\frac{4}{-12}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+7}{2*-6}=\frac{18}{-12}
=-1+1/2
$